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6x/x^2-36=0
Domain of the equation: x^2!=0We multiply all the terms by the denominator
x^2!=0/
x^2!=√0
x!=0
x∈R
6x-36*x^2=0
We add all the numbers together, and all the variables
-36x^2+6x=0
a = -36; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-36)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-36}=\frac{-12}{-72} =1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-36}=\frac{0}{-72} =0 $
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